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If I want to define jump url。But XCUIApplication don't have method:openurl。And if I use "[UIApplication sharedApplication]", it can't work。
I want to know how to solve it。
The text was updated successfully, but these errors were encountered:
If I want to define jump url。But XCUIApplication don't have method:openurl。And if I use "[UIApplication sharedApplication]", it can't work。
I want to know how to solve it。
The text was updated successfully, but these errors were encountered: