1309.解码字母到整数映射.py

#
# @lc app=leetcode.cn id=1309 lang=python3
#
# [1309] 解码字母到整数映射
#

# @lc code=start
class Solution:
    def freqAlphabets(self, s: str) -> str:
        def get(st):
            return chr(int(st) + 96)

        i, ans = 0, ""
        while i < len(s):
            if i + 2 < len(s) and s[i + 2] == '#':
                ans += get(s[i : i + 2])
                i += 2
            else:
                ans += get(s[i])
            i += 1
        return ans

# @lc code=end