How to get Chai to ignore HTML?

[zanenkn]

Problem

Background

Im working on FizzBuzz JS. Specs wouldn't pass because of the inner HTML that Chai is picking up (check out screenshots). Specs pass if I use include instead of eql but I wonder if there's a simple way of "telling" Chai to ignore the HTML tags and still perform the eql.

Spec

 const {FizzBuzz} = require('../spec.helper.js')

describe('Fizz Buzz', () => {
    let fizzBuzz = new FizzBuzz

    it("returns a number if no game rules are met", () => {
        expect(fizzBuzz.check(1)).to.eql(1)
    })

    it("returns Buzz if number is divisible by 5", () => {
        expect(fizzBuzz.check(5)).to.eql("Buzz")
    })

    it ("returns Fizz if number is divisible by 3", () => {
        expect(fizzBuzz.check(3)).to.eql("You entered 3. Fizz!")
    })

    it ("returns FizzBuzz if number is divisible by 15", () => {
        expect(fizzBuzz.check(15)).to.include("FizzBuzz!")
    })
})

Implementation code

function FizzBuzz()  {
    this.check = (number) => {
        if (number % 15 === 0){
            return `You entered ${number}. <br> <h1>FizzBuzz!</h1>`;
        } else if (number % 5 === 0){
            return `You entered ${number}. <br> <h1>Buzz!</h1>`;
        } else if (number % 3 === 0){
            return `You entered ${number}. <br> <h1>FizzBuzz!</h1>`;
        } else {
            return `You entered ${number}.`
        }
    }
}

Screenshots

How did you try to solve the problem?

Tried to turn the whole thing into string:

it ("returns Fizz if number is divisible by 3", () => {
        expect(String(fizzBuzz.check(3))).to.eql("You entered 3. Fizz!")
    })

(didn't work)

Read through Chai docs but didn't find anything useful.

[tochman]

Try using

.to.contain('text')

instead of

.to.eql('text')