forked from mehul-1607/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path_1380.java
67 lines (63 loc) · 2.04 KB
/
_1380.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.List;
/**
* 1380. Lucky Numbers in a Matrix
*
* Given a m * n matrix of distinct numbers, return all lucky numbers in the matrix in any order.
* A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
*
* Example 1:
* Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]
* Output: [15]
* Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
*
* Example 2:
* Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
* Output: [12]
* Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
*
* Example 3:
* Input: matrix = [[7,8],[1,2]]
* Output: [7]
*
* Constraints:
* m == mat.length
* n == mat[i].length
* 1 <= n, m <= 50
* 1 <= matrix[i][j] <= 10^5.
* All elements in the matrix are distinct.
* */
public class _1380 {
public static class Solution1 {
public List<Integer> luckyNumbers(int[][] matrix) {
List<Integer> result = new ArrayList<>();
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix[0].length; j++) {
if (luckyInRow(matrix[i][j], matrix[i])) {
if (luckyInColumn(matrix[i][j], matrix, j)) {
result.add(matrix[i][j]);
}
}
}
}
return result;
}
private boolean luckyInColumn(int number, int[][] matrix, int columnIndex) {
for (int i = 0; i < matrix.length; i++) {
if (number < matrix[i][columnIndex]) {
return false;
}
}
return true;
}
private boolean luckyInRow(int number, int[] row) {
for (int num : row) {
if (number > num) {
return false;
}
}
return true;
}
}
}