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Equation 8.1 #8

Answered by robjhyndman
Dmitrij548 asked this question in Q&A
Jan 5, 2025 · 1 comments · 3 replies
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It is not clear what $n$ is here. The length of the series in our notation is $T$.

The equation is deliberately infinite. That is, there is no end. Of course, there are a finite number of observations, so once we run out of observations, we have no way of computing the remaining terms.

If you expand the equation to include all observations, it is

$$\hat{y}_{T+1|T} = \alpha y_T + \alpha(1-\alpha) y_{T-1} + \alpha(1-\alpha)^2 y_{T-2} + \dots + \alpha(1-\alpha)^{T-1} y_{1} + c$$

where $c = (1-\alpha)^T \sum_{j=0}^{-\infty} \alpha(1-\alpha)^j y_{j}$ contains the unobserved terms. We can rewrite that as $c = (1-\alpha)^T\ell_0$, giving the weighted average form.

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fpp3 Forecasting: Principles and Practice 3rd edition
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