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Nested contrasts for 3 factors #33

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The answer that Reinhold gave in person in class was that you can either do y ~ 1 + F4/F2 as suggested in the question or do y ~ 1 + F1/F3/F2 (F2 nested under F3 and nested under F1)

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@kliegl
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Answer selected by tatiana-pashkova
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