leapyr_function.py

# An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.
# In the Gregorian calendar, three conditions are used to identify leap years:

# The year can be evenly divided by 4, is a leap year, unless:
# The year can be evenly divided by 100, it is NOT a leap year, unless:
# The year is also evenly divisible by 400. Then it is a leap year.
# This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. Source

# Task
# Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.
# Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.

def is_leap(year):
    leap = False
    
    # Write your logic here
    if (year % 4 == 0) and ((year % 400 == 0) or (year % 100 != 0)):
        return True
    else:
        return leap

year = int(input())
print(is_leap(year))