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1.5.2
https://github.com/Tencent/tdesign-vue/blob/develop/src/popup/container.tsx
打开t-popup时,不进行关闭窗口的操作时,此时切换路由到其他的页面时,该窗口无法关闭
destroyed() { if (typeof process !== 'undefined' && process.env?.NODE_ENV === 'test') return; this.unmountContent(); },
建议:源码popupt/container.tsx这个文件中去掉这边环节变量判断,不理解为什么加上这个判断,巧了我们业务测试环境正好是test,虽然说可以改,但是不去看源码 ,根本找不到这个问题原因
No response
The text was updated successfully, but these errors were encountered:
👋 @xinller,感谢给 TDesign 提出了 issue。 请根据 issue 模版确保背景信息的完善,我们将调查并尽快回复你。
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♥️ 有劳 @chaishi @Red626 @ikeq @honkinglin @Aicmortal @uyarn 尽快确认问题。 确认有效后将下一步计划和可能需要的时间回复给 @xinller 。
fixed in 1.6.5
ikeq
chaishi
honkinglin
uyarn
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tdesign-vue 版本
1.5.2
重现链接
https://github.com/Tencent/tdesign-vue/blob/develop/src/popup/container.tsx
重现步骤
打开t-popup时,不进行关闭窗口的操作时,此时切换路由到其他的页面时,该窗口无法关闭
期望结果
destroyed() {
if (typeof process !== 'undefined' && process.env?.NODE_ENV === 'test') return;
this.unmountContent();
},
建议:源码popupt/container.tsx这个文件中去掉这边环节变量判断,不理解为什么加上这个判断,巧了我们业务测试环境正好是test,虽然说可以改,但是不去看源码 ,根本找不到这个问题原因
实际结果
No response
框架版本
No response
浏览器版本
No response
系统版本
No response
Node版本
No response
补充说明
No response
The text was updated successfully, but these errors were encountered: