Given n
points
on a 2D plane where points[i] = [xi, yi]
, Return the widest vertical area between two points such that no points are inside the area.
A vertical area is an area of fixed-width extending infinitely along the y-axis (i.e., infinite height). The widest vertical area is the one with the maximum width.
Note that points on the edge of a vertical area are not considered included in the area.
Example 1:
Input: points = [[8,7],[9,9],[7,4],[9,7]] Output: 1 Explanation: Both the red and the blue area are optimal.
Example 2:
Input: points = [[3,1],[9,0],[1,0],[1,4],[5,3],[8,8]] Output: 3
Constraints:
n == points.length
2 <= n <= 105
points[i].length == 2
0 <= xi, yi <= 109
Related Topics:
Sort
Sort the points in ascending order of x
values, then traverse to find the maximum distance of x
values between adjacent points.
// OJ: https://leetcode.com/problems/widest-vertical-area-between-two-points-containing-no-points/
// Author: github.com/lzl124631x
// Time: O(NlogN)
// Space: O(1)
class Solution {
public:
int maxWidthOfVerticalArea(vector<vector<int>>& A) {
sort(begin(A), end(A), [](auto &a, auto &b) { return a[0]< b[0]; });
int ans = 0;
for (int i = 1; i < A.size(); ++i) ans = max(ans, A[i][0] - A[i - 1][0]);
return ans;
}
};