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blktrace-fio对比测试分析.html
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blktrace+fio对比测试分析
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<a href="/blktrace-fio对比测试分析.html" class="archive-article-date">
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<p>利用BLKTRACE分析磁盘IO </p>
<p>在Linux系统上,查看磁盘的负载情况,咱们一般使用iostat监控工具,iostat的详细介绍查看另外的培训资料。其中很重要的参数就是await,await表示单个I/O所需的平均时间,但它同时包含了I/O Scheduler所消耗的时间和硬件所消耗的时间,所以不能作为硬件性能的指标。那如何才能分辨一个io从下发到返回整个时间上,是硬件层耗时多还是在io调度上耗时多呢?如何查看io在各个时间段所消耗的时间呢?那么,blktrace在这种场合就能派上用场,因为它能记录I/O所经历的各个步骤,从中可以分析是IO Scheduler慢还是硬件响应慢,以及各个时间段所用时间。<br><a id="more"></a><br>blktrace的原理<br>一个I/O请求进入block layer之后,可能会经历下面的过程:</p>
<ul>
<li>Remap: 可能被DM(Device Mapper)或MD(Multiple Device, Software RAID) remap到其它设备</li>
<li>Split: 可能会因为I/O请求与扇区边界未对齐、或者size太大而被分拆(split)成多个物理I/O</li>
<li>Merge: 可能会因为与其它I/O请求的物理位置相邻而合并(merge)成一个I/O</li>
</ul>
<ul>
<li>被IO Scheduler依照调度策略发送给driver</li>
</ul>
<ul>
<li>被driver提交给硬件,经过HBA、电缆(光纤、网线等)、交换机(SAN或网络)、最后到达存储设备,设备完成IO请求之后再把结果发回。</li>
</ul>
<p>blktrace能记录I/O所经历的各个步骤,来看一下它记录的数据,包含9个字段,下图标示了其中8个字段的含义,大致的意思是“哪个进程在访问哪个硬盘的哪个扇区,进行什么操作,进行到哪个步骤,时间戳是多少”:<br><img src="https://i.imgur.com/tyws5Pz.png" alt=""></p>
<ul>
<li>第一个字段:8,0 这个字段是设备号 major device ID和minor device ID。-第二个字段:3 表示CPU</li>
<li>第三个字段:11 序列号</li>
<li>第四个字段:0.009507758 Time Stamp是时间偏移</li>
<li>第五个字段:PID 本次IO对应的进程ID</li>
<li>第六个字段:Event,这个字段非常重要,反映了IO进行到了那一步</li>
<li>第七个字段:R表示 Read, W是Write,D表示block,B表示BarrierOperation</li>
<li>第八个字段:223490+56,表示的是起始block number 和 number of blocks,即我们常说的Offset 和 Size(扇区??)</li>
<li>第九个字段: 进程名</li>
</ul>
<p>其中第六个字段非常有用:每一个字母都代表了IO请求所经历的某个阶段。</p>
<ul>
<li>A 映射值对应设备 IO was remapped to a different device</li>
<li>B IO反弹,由于32位地址长度限制,所以需要copy数据到低位内存,这会有性能损耗。IO bounced</li>
<li>C IO完成 IO completion</li>
<li>D 将IO发送给驱动 IO issued to driver</li>
<li>F IO请求,前合并 IO front merged with request on queue</li>
<li>G 获取 请求 Get request</li>
<li>I IO插入请求队列 IO inserted onto request queue</li>
<li>M IO请求,后合并 IO back merged with request on queue</li>
<li>P 插上块设备队列(队列插入机制) Plug request</li>
<li>Q io被请求队列处理代码接管。 IO handled by request queue code</li>
<li>S 等待发送请求。 Sleep request</li>
<li>T 由于超时而拔出设备队列 Unplug due to timeout</li>
<li>U 拔出设备队列 Unplug request</li>
<li>X 开始新的扇区 Split</li>
</ul>
<p>其中最重要的几个阶段如下:</p>
<pre><code>Q – 即将生成IO请求
|
G – IO请求生成
|
I – IO请求进入IO Scheduler队列
|
D – IO请求进入driver
|
C – IO请求执行完毕
</code></pre><p>根据以上步骤对应的时间戳就可以计算出I/O请求在每个阶段所消耗的时间:</p>
<pre><code>Q2G – 生成IO请求所消耗的时间,包括remap和split的时间;
G2I – IO请求进入IO Scheduler所消耗的时间,包括merge的时间;
I2D – IO请求在IO Scheduler中等待的时间;
D2C – IO请求在driver和硬件上所消耗的时间;
Q2C – 整个IO请求所消耗的时间(Q2I + I2D + D2C = Q2C),相当于iostat的await。
</code></pre><p>btt工具,blkparse等参考<a href="http://www.idcat.cn/2018/04/21/blktrace-%E5%B7%A5%E5%85%B7%E7%AE%80%E4%BB%8B/" title="http://www.idcat.cn/2018/04/21/blktrace-%E5%B7%A5%E5%85%B7%E7%AE%80%E4%BB%8B/" target="_blank" rel="noopener">http://www.idcat.cn/2018/04/21/blktrace-%E5%B7%A5%E5%85%B7%E7%AE%80%E4%BB%8B/</a></p>
<h1 id="测试"><a href="#测试" class="headerlink" title="测试"></a>测试</h1><p><strong>1、4k direct=1</strong> </p>
<p>通过fio对本地磁盘sdc挂载点进行4K小文件顺序写测试,期间监控磁盘信息。完成fio测试后,手动终止监控程序,然后进行数据分析。并与iostat的数据进行对比分析。</p>
<p>fio 开启测试</p>
<pre><code>[root@node1 samba-test]# fio -filename=./4k_file -direct=1 -iodepth=1 -thread -rw=write -ioengine=libaio -bs=4k -size=3G -numjobs=4 -times=300 -group_reporting -name=mytest2
mytest2: (g=0): rw=write, bs=4K-4K/4K-4K/4K-4K, ioengine=libaio, iodepth=1
...
fio-2.2.5
Starting 4 threads
</code></pre><p>注意:</p>
<p>1、direct=1即o_direct直写io。不会经过系统缓存,即没有合并</p>
<p>2、numjobs=4 bs=4k 对应iostat即队列深度为4.</p>
<p>3、bs=4k 对应iostat扇区数为8 </p>
<p>开启监控磁盘sdc</p>
<pre><code>[root@node1 ~]# blktrace -d /dev/sdc
</code></pre><p>iostat监控</p>
<p><img src="https://i.imgur.com/pbfZKtL.jpg" alt=""></p>
<p>FIO运行结束后,终止blktrace进程</p>
<p>收集数据</p>
<pre><code>[root@node1 fioblk]# blktrace -d /dev/sdc
^C=== sdc ===
CPU 0: 5504242 events, 258012 KiB data
CPU 1: 5693967 events, 266905 KiB data
Total: 11198209 events (dropped 0), 524917 KiB data
[root@node1 fioblk]# ll
total 524920
-rw-r--r-- 1 root root 264203656 Apr 27 14:08 sdc.blktrace.0
-rw-r--r-- 1 root root 273310432 Apr 27 14:08 sdc.blktrace.1
[root@node1 fioblk]#
</code></pre><p>会看到生成文件数以当前cpu个数命名。</p>
<p>生成数据</p>
<p>blkparse -i sdc -d sdc.blktrace.bin</p>
<p>会将所有数据汇总到文件sdc.blktrace.bin里面。期间我截图了如下,代表3个io的过程。对比上面介绍。<br> <img src="https://i.imgur.com/nGTPClj.jpg" alt=""><br>WS表示同步写</p>
<p>分析数据</p>
<p>生成所有数据,后面介绍针对性的数据。</p>
<pre><code>[root@node1 fioblk]# btt -i sdc.blktrace.bin -A |less
</code></pre><p><img src="https://i.imgur.com/QbV8sv4.jpg" alt=""></p>
<ul>
<li>Q2G – 生成IO请求所消耗的时间,包括remap和split的时间;本例0.009ms</li>
<li>G2I – IO请求进入IO Scheduler所消耗的时间,包括merge的时间;0.001ms</li>
<li>I2D – IO请求在IO Scheduler中等待的时间;0.0009ms</li>
<li>D2C – IO请求在driver和硬件上所消耗的时间;0.7ms</li>
</ul>
<p>因此:</p>
<p>Q2C – 整个IO请求所消耗的时间(Q2I + I2D + D2C = Q2C),相当于iostat的await。 几乎0.78ms与iostat wait值一致。在io scheduler上几乎没有消耗任何时间。</p>
<p>生成iops 和bw每秒值</p>
<pre><code>btt -i sdc.blktrace.bin -q sdc.q2c_latency
total 1079400
-rw-r--r-- 1 root root 2759 Apr 27 14:45 8,32_iops_fp.dat
-rw-r--r-- 1 root root 4340 Apr 27 14:45 8,32_mbps_fp.dat
-rw-r--r-- 1 root root 264203656 Apr 27 14:08 sdc.blktrace.0
-rw-r--r-- 1 root root 273310432 Apr 27 14:08 sdc.blktrace.1
-rw-r--r-- 1 root root 537514088 Apr 27 14:16 sdc.blktrace.bin
-rw-r--r-- 1 root root 30244692 Apr 27 14:45 sdc.q2c_latency_8,32_q2c.dat
-rw-r--r-- 1 root root 2759 Apr 27 14:45 sys_iops_fp.dat
-rw-r--r-- 1 root root 4340 Apr 27 14:45 sys_mbps_fp.dat
</code></pre><p>生成io大小分布</p>
<pre><code>btt -i sdc.blktrace.bin -B sdc.offset
[root@node1 fioblk]# ll
total 1183168
-rw-r--r-- 1 root root 2759 Apr 27 14:57 8,32_iops_fp.dat
-rw-r--r-- 1 root root 4340 Apr 27 14:57 8,32_mbps_fp.dat
-rw-r--r-- 1 root root 264203656 Apr 27 14:08 sdc.blktrace.0
-rw-r--r-- 1 root root 273310432 Apr 27 14:08 sdc.blktrace.1
-rw-r--r-- 1 root root 537514088 Apr 27 14:16 sdc.blktrace.bin
-rw-r--r-- 1 root root 53125272 Apr 27 14:57 sdc.offset_8,32_c.dat
-rw-r--r-- 1 root root 53125272 Apr 27 14:57 sdc.offset_8,32_w.dat
</code></pre><p>本例只有write,所有生成了_w _c 写是w 读是r c是w+c 本例c和w一样大。查看文件内容</p>
<pre><code>0.000002716 52608272 52608280
0.000129844 52608000 52608008
0.000324497 52607688 52607696
0.000927928 52606144 52606152
0.001015187 52608280 52608288
0.001449302 52608008 52608016
</code></pre><p>第一行为时间,第二个为其实扇区大小,第3行为每个io结束扇区大小。可以算出每个io为8个扇区大小,既4k 与测试实际相符合。</p>
<p><strong>2、1M direct=1</strong></p>
<p>fio运行</p>
<pre><code>[root@node1 samba-test]# fio -filename=./1m_file -direct=1 -iodepth=1 -thread -rw=write -ioengine=libaio -bs=1M -size=3G -numjobs=4 -times=300 -group_reporting -name=mytest2
mytest2: (g=0): rw=write, bs=1M-1M/1M-1M/1M-1M, ioengine=libaio, iodepth=1
...
fio-2.2.5
Starting 4 threads
mytest2: Laying out IO file(s) (1 file(s) / 3072MB)
</code></pre><p>注意:</p>
<ul>
<li>1、bs=1M ,sdc块设备最大单次io大小为512,因此会分为2个io写入,numjobs=4,因此队列深度为2*4 = 8 </li>
<li>[root@node1 1m]# cat /sys/block/sdc/queue/max_sectors_kb<br>512</li>
<li>[root@node1 ~]# cat /sys/block/sdc/queue/nr_requests<br>128 磁盘最大队列深度。</li>
<li>2、bs=1M 最大io数为512kb,除以512byte扇区大小为操作扇区数1024<br>与iostat一致。</li>
</ul>
<p>blktrace取值</p>
<pre><code>[root@node1 1m]# blktrace -d /dev/sdc
</code></pre><p>iostat取值<br><img src="https://i.imgur.com/O8hjNoU.jpg" alt=""></p>
<p>fio运行完成后,生成数据,并分析数据</p>
<p>生成数据</p>
<pre><code>[root@node1 1m]# blkparse -i sdc -d sdc.blktrace.bin
</code></pre><p><img src="https://i.imgur.com/5YcmCt4.jpg" alt=""></p>
<p>可以看到Q-C一个完整的io路径。右边起始扇区+1024个扇区数。与实际相符合。</p>
<p>分析数据</p>
<pre><code>root@node1 1m]# btt -i sdc.blktrace.bin -A | less
</code></pre><p><img src="https://i.imgur.com/FiYWzt6.jpg" alt=""></p>
<ul>
<li>Q2G – 生成IO请求所消耗的时间,包括remap和split的时间;<br>本例0.7ms 因为有块分为2部分。1m分为2个512kb io,单个512kb io 到扇区后得与扇区对齐等等</li>
<li>G2I – IO请求进入IO Scheduler所消耗的时间,包括merge的时间;<br>0.009ms 没有进行合并 绕过缓存了。</li>
<li>I2D – IO请求在IO Scheduler中等待的时间;<br>2.8ms</li>
<li>D2C – IO请求在driver和硬件上所消耗的时间;<br>34.5 ms</li>
</ul>
<p>因此:</p>
<p>Q2C – 整个IO请求所消耗的时间(Q2I + I2D + D2C = Q2C),相当于iostat的await。 为38.1ms与iostat wait值几乎一致。在io scheduler上几乎没有消耗任何时间。时间花费在driver硬件层。</p>
<p>生成iops 和bw每秒值</p>
<pre><code>btt -i sdc.blktrace.bin -q sdc.q2c_latency
[root@node1 1m]# ll
total 14508
-rw-r--r-- 1 root root 913 Apr 27 15:40 8,32_iops_fp.dat
-rw-r--r-- 1 root root 1731 Apr 27 15:40 8,32_mbps_fp.dat
-rw-r--r-- 1 root root 3295528 Apr 27 15:20 sdc.blktrace.0
-rw-r--r-- 1 root root 3894704 Apr 27 15:20 sdc.blktrace.1
-rw-r--r-- 1 root root 7190232 Apr 27 15:28 sdc.blktrace.bin
-rw-r--r-- 1 root root 452027 Apr 27 15:40 sdc.q2c_latency_8,32_q2c.dat
-rw-r--r-- 1 root root 913 Apr 27 15:40 sys_iops_fp.dat
-rw-r--r-- 1 root root 1731 Apr 27 15:40 sys_mbps_fp.dat
</code></pre><p>生成io大小分布</p>
<pre><code>btt -i sdc.blktrace.bin -B sdc.offset
[root@node1 1m]# ll
total 16148
-rw-r--r-- 1 root root 913 Apr 27 15:44 8,32_iops_fp.dat
-rw-r--r-- 1 root root 1731 Apr 27 15:44 8,32_mbps_fp.dat
-rw-r--r-- 1 root root 3295528 Apr 27 15:20 sdc.blktrace.0
-rw-r--r-- 1 root root 3894704 Apr 27 15:20 sdc.blktrace.1
-rw-r--r-- 1 root root 7190232 Apr 27 15:28 sdc.blktrace.bin
-rw-r--r-- 1 root root 835954 Apr 27 15:44 sdc.offset_8,32_c.dat
-rw-r--r-- 1 root root 835954 Apr 27 15:44 sdc.offset_8,32_w.dat
-rw-r--r-- 1 root root 452027 Apr 27 15:40 sdc.q2c_latency_8,32_q2c.dat
-rw-r--r-- 1 root root 913 Apr 27 15:44 sys_iops_fp.dat
-rw-r--r-- 1 root root 1731 Apr 27 15:44 sys_mbps_fp.dat
</code></pre><p>只有写,即_w 与_c一致。查看_w文件sdc.offset_8,32_w.dat</p>
<pre><code>127.845942908 65054784 65055808
127.846185883 65055808 65056832
127.952831800 65056832 65057856
127.953065986 65057856 65058880
127.955207647 65058880 65059904
</code></pre><p>第一行为时间,第二个为其实扇区大小,第3行为每个io结束扇区大小。可以算出每个io为1024个扇区大小,既1M 与测试实际相符合。</p>
<p><strong>3、4k direct=0</strong></p>
<pre><code>[root@node1 samba-test]# fio -filename=./4k_file_direct0 -direct=0 -iodepth=1 -thread -rw=write -ioengine=libaio -bs=4k -size=3G -numjobs=4 -times=300 -group_reporting -name=mytest2
mytest2: (g=0): rw=write, bs=4K-4K/4K-4K/4K-4K, ioengine=libaio, iodepth=1
...
fio-2.2.5
Starting 4 threads
mytest2: Laying out IO file(s) (1 file(s) / 3072MB)
</code></pre><ul>
<li>direct=0后 启动io buffer </li>
</ul>
<p>iostat监控<br><img src="https://i.imgur.com/ap1qitG.jpg" alt=""></p>
<p>blktrace监控数据</p>
<p>生成数据</p>
<pre><code>[root@node1 1m]# blkparse -i sdc -d sdc.blktrace.bin
</code></pre><p><img src="https://i.imgur.com/wm94VIu.jpg" alt=""></p>
<p>4k对象大小,在io路径变成1024 既最大512kb字节,很明显进行IO合并,大部分io动作都是Q G I来回循环,即生成io请求到io请求队列,就返回继续申请新的io到队列,整体由内核kworker进行io任务的调度,在内存swapper中完成io写入。W表示异步写。</p>
<p>分析数据</p>
<pre><code>[root@node1 1m]# btt -i sdc.blktrace.bin -A | less
</code></pre><p><img src="https://i.imgur.com/sVzF5Lq.jpg" alt=""></p>
<ul>
<li>Q2G – 生成IO请求所消耗的时间,包括remap和split的时间;<br>本例5.6ms</li>
<li>G2I – IO请求进入IO Scheduler所消耗的时间,包括merge的时间;<br>0.009ms 没有进行合并。</li>
<li>I2D – IO请求在IO Scheduler中等待的时间;<br>635 ms</li>
<li>D2C – IO请求在driver和硬件上所消耗的时间;<br>188 ms</li>
<li>Q2C – 整个IO请求所消耗的时间(Q2I + I2D + D2C = Q2C),相当于iostat的await。 为828.6ms与iostat wait值几乎一致。在io scheduler上消耗太多时间。在driver硬件层耗时相对少一些,但是也很大了达到188ms。<br>其中M2D io合并时间平均4.5s.</li>
</ul>
<p>生成io大小分布</p>
<pre><code>btt -i sdc.blktrace.bin -B sdc.offset
93.463618386 74670904 74671928
93.463870465 74671928 74672952
93.464140190 74672952 74673976
93.464445965 74673976 74675000
93.464740898 74675000 74676024
93.465027976 74676024 74677048
93.465313376 74677048 74678072
</code></pre><p>同样的是以1024个扇区为最小io。</p>
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