https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/
Given an integer array nums
sorted in non-decreasing order, remove the duplicates in-place such that each unique
element
appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements
in nums
.
Consider the number of unique elements of nums
to be k
, to get accepted, you need to do the following things:
- Change the array
nums
such that the firstk
elements of nums contain the unique elements in the order they were present in nums initially. The remaining elements ofnums
are not important as well as the size ofnums
. - Return
k
.
Input: nums = [1,1,2]
Output: 2, nums = [1,2,_]
Explanation: Your function should return k = 2
, with the first two elements of nums
being 1 and 2 respectively.
It does not matter what you leave beyond the returned k
(hence they are underscores).
Input: nums = [0,0,1,1,1,2,2,3,3,4]
Output: 5, nums = [0,1,2,3,4,_,_,_,_,_]
Explanation: Your function should return k = 5
, with the first five elements of nums
being 0, 1, 2, 3, and 4
respectively. It does not matter what you leave beyond the returned k
(hence they are underscores).
1 <= nums.length <= 3 * 104
-100 <= nums[i] <= 100
nums is sorted in non-decreasing order.