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test.uml
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test.uml
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<?xml version="1.0" encoding="UTF-8"?>
<uml:Model xmi:version="2.1" xmlns:xmi="http://schema.omg.org/spec/XMI/2.1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:uml="http://www.eclipse.org/uml2/3.0.0/UML" xmi:id="_-jMIQRKeEeaKjdK582j3uA">
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<body>/**
* @author daniel
* @time 2016-4-14 下午2:54:40
* @param args
*/
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<body>/**
* 单调递增最长子序列
* 时间限制：3000 ms | 内存限制：65535 KB
* 难度：4
* 描述
* 求一个字符串的最长递增子序列的长度
* 如：dabdbf最长递增子序列就是abdf，长度为4
* 输入
* 第一行一个整数0<n<20,表示有n个字符串要处理
* 随后的n行，每行有一个字符串，该字符串的长度不会超过10000
* 输出
* 输出字符串的最长递增子序列的长度
* 样例输入
* 3
* aaa
* ababc
* abklmncdefg
* 样例输出
* 1
* 3
* 7
* @author daniel
* @email [email protected]
* @time 2016-4-27 下午12:33:47
*/
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<upperValue xmi:type="uml:LiteralUnlimitedNatural" xmi:id="_-yERwRKeEeaKjdK582j3uA" value="*"/>
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<body>/**
* @author daniel
* @email [email protected]
* @time 2016-4-13 下午6:09:14
*/
</body>
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<body>/**
* 长度
*/
</body>
</ownedComment>
<type xmi:type="uml:PrimitiveType" href="pathmap://UML_LIBRARIES/JavaPrimitiveTypes.library.uml#double"/>
<defaultValue xmi:type="uml:LiteralInteger" xmi:id="_-yJxURKeEeaKjdK582j3uA" value="20"/>
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<body>/**
* 高度宽度
*/
</body>
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<type xmi:type="uml:PrimitiveType" href="pathmap://UML_LIBRARIES/JavaPrimitiveTypes.library.uml#double"/>
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<body>/**
* @author daniel
* @time 2016-4-13 下午5:40:50
* @param args
*/
</body>
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<body>/**
* 描述
* 一个街区有很多住户，街区的街道只能为东西、南北两种方向。
* 住户只可以沿着街道行走。
* 各个街道之间的间隔相等。
* 用(x,y)来表示住户坐在的街区。
* 例如（4,20），表示用户在东西方向第4个街道，南北方向第20个街道。
* 现在要建一个邮局，使得各个住户到邮局的距离之和最少。
* 求现在这个邮局应该建在那个地方使得所有住户距离之和最小；
* 输入
* 第一行一个整数n<20，表示有n组测试数据，下面是n组数据;
* 每组第一行一个整数m<20,表示本组有m个住户，下面的m行每行有两个整数0<x,y<100，表示某个用户所在街区的坐标。
* m行后是新一组的数据；
* 输出
* 每组数据输出到邮局最小的距离和，回车结束；
* 样例输入
* 2
* 3
* 1 1
* 2 1
* 1 2
* 5
* 2 9
* 5 20
* 11 9
* 1 1
* 1 20
* 样例输出
* 2
* 44
* 分析:
* 每个住户分左边X,Y。穷举法
* 1.计算出一个坐标点分别到每个住户的距离，然后相加。
* 2.计算出所有坐标点到输入住户的距离，保留最小距离
* @author daniel
* @email [email protected]
* @time 2016-4-14 下午3:56:29
*/
</body>
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<type xmi:type="uml:PrimitiveType" href="pathmap://UML_LIBRARIES/JavaPrimitiveTypes.library.uml#int"/>
<defaultValue xmi:type="uml:LiteralInteger" xmi:id="_-yUwcRKeEeaKjdK582j3uA"/>
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<body>/**
* @author daniel
* @time 2016-4-14 下午3:09:34
* @param args
*/
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<ownedParameter xmi:id="_-yV-kRKeEeaKjdK582j3uA" name="args">
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<upperValue xmi:type="uml:LiteralUnlimitedNatural" xmi:id="_-yV-khKeEeaKjdK582j3uA" value="*"/>
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<body>/**
* 计算最短距离
* @author daniel
* @time 2016-4-14 下午3:52:01
* @param user
*/
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<body>/**
* 擅长排列的小明
* 时间限制：1000 ms | 内存限制：65535 KB
* 难度：4
* 描述
* 小明十分聪明，而且十分擅长排列计算。比如给小明一个数字5，他能立刻给出1-5按字典序的全排列，如果你想为难他，在这5个数字中选出几个数字让他继续全排列，那么你就错了，他同样的很擅长。现在需要你写一个程序来验证擅长排列的小明到底对不对。
* 输入
* 第一行输入整数N（1<N<10）表示多少组测试数据，
* 每组测试数据第一行两个整数 n m (1<n<9,0<m<=n)
* 输出
* 在1-n中选取m个字符进行全排列，按字典序全部输出,每种排列占一行，每组数据间不需分界。如样例
* 样例输入
* 2
* 3 1
* 4 2
* 样例输出
* 1
* 2
* 3
* 12
* 13
* 14
* 21
* 23
* 24
* 31
* 32
* 34
* 41
* 42
* 43
* @author daniel
* @email [email protected]
* @time 2016-4-27 下午12:32:37
*/
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<body>/**
* @param args
*/
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<body>/**
* 矩形嵌套
* 时间限制：3000 ms | 内存限制：65535 KB
* 难度：4
* 描述
* 有n个矩形，每个矩形可以用a,b来描述，表示长和宽。矩形X(a,b)可以嵌套在矩形Y(c,d)中当且仅当a<c,b<d或者b<c,a<d（相当于旋转X90度）。例如（1,5）可以嵌套在（6,2）内，但不能嵌套在（3,4）中。你的任务是选出尽可能多的矩形排成一行，使得除最后一个外，每一个矩形都可以嵌套在下一个矩形内。
* 输入
* 第一行是一个正正数N(0<N<10)，表示测试数据组数，
* 每组测试数据的第一行是一个正正数n，表示该组测试数据中含有矩形的个数(n<=1000)
* 随后的n行，每行有两个数a,b(0<a,b<100)，表示矩形的长和宽
* 输出
* 每组测试数据都输出一个数，表示最多符合条件的矩形数目，每组输出占一行
* 样例输入
* 1
* 10
* 1 2
* 2 4
* 5 8
* 6 10
* 7 9
* 3 1
* 5 8
* 12 10
* 9 7
* 2 2
* 样例输出
* 5
* @author daniel
* @email [email protected]
* @time 2016-4-25 下午1:46:22
*/
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<ownedComment xmi:id="_-ycsQBKeEeaKjdK582j3uA">
<body>/**
* @author daniel
* @time 2016-4-25 下午12:18:52
* @param args
*/
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<ownedParameter xmi:id="_-ybeIRKeEeaKjdK582j3uA" name="args">
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<body>/**
* ID,长宽对象
* @author daniel
* @email [email protected]
* @time 2016-4-15 上午11:47:27
*/
</body>
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<body>/**
* 描述 现有一块草坪，长为20米，宽为2米，要在横中心线上放置半径为Ri的喷水装置，每个喷水装置的效果都会让以它为中心的半径为实数Ri(0<Ri<15)
* 的圆被湿润，这有充足的喷水装置i（1<i<600)个，并且一定能把草坪全部湿润，你要做的是：选择尽量少的喷水装置，把整个草坪的全部湿润。 输入
* 第一行m表示有m组测试数据 每一组测试数据的第一行有一个整数数n，n表示共有n个喷水装置，随后的一行，有n个实数ri，ri表示该喷水装置能覆盖的圆的半径。
* 输出 输出所用装置的个数 样例输入 2 5 2 3.2 4 4.5 6 10 1 2 3 1 2 1.2 3 1.1 1 2 样例输出 2 5
* 思路：求出三角形另一侧边的长度。半径平方-（宽/2）平方
* @author daniel
* @email [email protected]
* @time 2016-4-13 下午6:09:14
*/
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<ownedComment xmi:id="_-yr80BKeEeaKjdK582j3uA">
<body>/**
* 长度
*/
</body>
</ownedComment>
<type xmi:type="uml:PrimitiveType" href="pathmap://UML_LIBRARIES/JavaPrimitiveTypes.library.uml#double"/>
<defaultValue xmi:type="uml:LiteralInteger" xmi:id="_-yrVwRKeEeaKjdK582j3uA" value="20"/>
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<ownedComment xmi:id="_-ytyABKeEeaKjdK582j3uA">
<body>/**
* 高度宽度
*/
</body>
</ownedComment>
<type xmi:type="uml:PrimitiveType" href="pathmap://UML_LIBRARIES/JavaPrimitiveTypes.library.uml#double"/>
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<ownedComment xmi:id="_-yvAIBKeEeaKjdK582j3uA">
<body>/**
* @author daniel
* @time 2016-4-13 下午5:40:50
* @param args
*/
</body>
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<ownedParameter xmi:id="_-ytyAhKeEeaKjdK582j3uA" name="args">
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<body>/**
* 奇偶数分离 时间限制：3000 ms | 内存限制：65535 KB 难度：1 描述 有一个整型偶数n(2<= n
* <=10000),你要做的是：先把1到n中的所有奇数从小到大输出，再把所有的偶数从小到大输出。 输入 第一行有一个整数i（2<=i<30)表示有 i
* 组测试数据； 每组有一个整型偶数n。 输出 第一行输出所有的奇数 第二行输出所有的偶数 样例输入 2 10 14 样例输出 1 3 5 7 9 2 4 6
* 8 10
* 1 3 5 7 9 11 13 2 4 6 8 10 12 14
* @author daniel
* @email [email protected]
* @time 2016-4-18 下午2:10:55
*/
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<body>/**
* @author daniel
* @time 2016-4-18 下午1:49:12
* @param args
*/
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<body>/**
* 描述
* 输入三个字符（可以重复）后，按各字符的ASCII码从小到大的顺序输出这三个字符。
* 输入
* 第一行输入一个数N,表示有N组测试数据。后面的N行输入多组数据，每组输入数据都是占一行，有三个字符组成，之间无空格。
* 输出
* 对于每组输入数据，输出一行，字符中间用一个空格分开。
* 样例输入
* 2
* qwe
* asd
* 样例输出
* e q w
* a d s
* @author daniel
* @email [email protected]
* @time 2016-4-13 下午3:47:42
*/
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<ownedComment xmi:id="_-yw1UBKeEeaKjdK582j3uA">
<body>/**
* @author daniel
* @time 2016-4-13 下午3:16:33
* @param args
*/
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<upperValue xmi:type="uml:LiteralUnlimitedNatural" xmi:id="_-ywOQhKeEeaKjdK582j3uA" value="*"/>
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<body>/**
* 排序
* @author daniel
* @time 2016-4-13 下午3:20:44
* @param str
*/
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<body>/**
* 描述
* 现在，有一行括号序列，请你检查这行括号是否配对。
* 输入
* 第一行输入一个数N（0<N<=100）,表示有N组测试数据。后面的N行输入多组输入数据，每组输入数据都是一个字符串S(S的长度小于10000，且S不是空串），测试数据组数少于5组。数据保证S中只含有"[","]","(",")"四种字符
* 输出
* 每组输入数据的输出占一行，如果该字符串中所含的括号是配对的，则输出Yes,如果不配对则输出No
* 样例输入
* 3
* [(])
* (])
* ([[]()])
* Stack 类表示后进先出（LIFO）的对象堆栈。它通过五个操作对类 Vector 进行了扩展 ，允许将向量视为堆栈。它提供了通常的 push 和 pop
* 操作，以及取堆栈顶点的 peek 方法、测试堆栈是否为空的 empty 方法、在堆栈中查找项并确定到堆栈顶距离的 search 方法。
* @author daniel
* @email [email protected]
* @time 2016-4-12 下午6:56:30
*/
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<ownedComment xmi:id="_-y-QsBKeEeaKjdK582j3uA">
<body>/**
* @author daniel
* @time 2016-4-12 下午6:30:07
* @param args
*/
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<upperValue xmi:type="uml:LiteralUnlimitedNatural" xmi:id="_-y9pohKeEeaKjdK582j3uA" value="*"/>
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<body>/**
* 实现细节
* @author daniel
* @time 2016-4-12 下午6:59:49
* @param str
* @return
*/
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<body>/**
* 描述 无穷数列1，1，2，3，5，8，13，21，34，55...称为Fibonacci数列，它可以递归地定义为 F(n)=1
* ...........(n=1或n=2) F(n)=F(n-1)+F(n-2).....(n>2) 现要你来求第n个斐波纳奇数。（第1个、第二个都为1)
* 输入 第一行是一个整数m(m<5)表示共有m组测试数据 每次测试数据只有一行，且只有一个整形数n(n<20) 输出
* 对每组输入n，输出第n个Fibonacci数 样例输入 3 1 3 5 样例输出 1 2 5
* @author daniel
* @email [email protected]
* @time 2016-4-21 上午11:28:28
*/
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<body>/**
* @author daniel
* @time 2016-4-21 上午10:34:13
* @param args
*/
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<body>/**
* 递归实现
* @author daniel
* @time 2016-4-21 上午11:37:33
* @param n
* @return
*/
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<body>/**
* 循环实现 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610,
*/
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<body>/**
* 会场安排问题
* 时间限制：3000 ms | 内存限制：65535 KB
* 难度：4
* 描述
* 学校的小礼堂每天都会有许多活动，有时间这些活动的计划时间会发生冲突，需要选择出一些活动进行举办。小刘的工作就是安排学校小礼堂的活动，每个时间最多安排一个活动。现在小刘有一些活动计划的时间表，他想尽可能的安排更多的活动，请问他该如何安排。
* 输入
* 第一行是一个整型数m(m<100)表示共有m组测试数据。
* 每组测试数据的第一行是一个整数n(1<n<10000)表示该测试数据共有n个活动。
* 随后的n行，每行有两个正整数Bi,Ei(0<=Bi,Ei<10000),分别表示第i个活动的起始与结束时间（Bi<=Ei)
* 输出
* 对于每一组输入，输出最多能够安排的活动数量。
* 每组的输出占一行
* 样例输入
* 2
* 2
* 1 10
* 10 11
* 3
* 1 10
* 10 11
* 11 20
* 样例输出
* 1
* 2
* 提示
* 注意：如果上一个活动在t时间结束，下一个活动最早应该在t+1时间开始
* @author daniel
* @email [email protected]
* @time 2016-4-22 下午4:47:50
*/
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<body>/**
* @author daniel
* @time 2016-4-22 下午3:49:51
* @param args
*/
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<body>/**
* 任务时间
* @author daniel
* @email [email protected]
* @time 2016-4-22 下午3:56:28
*/
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<body>/**
* 按照结束时间从小到大排序
*/
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<body>/**
* 一种排序
* 时间限制：3000 ms | 内存限制：65535 KB
* 难度：3
* 描述
* 现在有很多长方形，每一个长方形都有一个编号，这个编号可以重复；还知道这个长方形的宽和长，编号、长、宽都是整数；现在要求按照一下方式排序（默认排序规则都是从小到大）；
* 1.按照编号从小到大排序
* 2.对于编号相等的长方形，按照长方形的长排序；
* 3.如果编号和长都相同，按照长方形的宽排序；
* 4.如果编号、长、宽都相同，就只保留一个长方形用于排序,删除多余的长方形；最后排好序按照指定格式显示所有的长方形；
* 输入
* 第一行有一个整数 0<n<10000,表示接下来有n组测试数据；
* 每一组第一行有一个整数 0<m<1000，表示有m个长方形；
* 接下来的m行，每一行有三个数 ，第一个数表示长方形的编号，
* 第二个和第三个数值大的表示长，数值小的表示宽，相等
* 说明这是一个正方形（数据约定长宽与编号都小于10000）；
* 输出
* 顺序输出每组数据的所有符合条件的长方形的 编号 长 宽
* 样例输入
* 1
* 8
* 1 1 1
* 1 1 1
* 1 1 2
* 1 2 1
* 1 2 2
* 2 1 1
* 2 1 2
* 2 2 1
* 样例输出
* 1 1 1
* 1 2 1
* 1 2 2
* 2 1 1
* 2 2 1
* I.思路
* II.矫正输入的数据 长宽互换
* II.判断是否已存在，存在则忽略
* II.对所有数据进行排序输出
* @author daniel
* @email [email protected]
* @time 2016-4-15 上午11:43:12
*/
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<body>/**
* @author daniel
* @time 2016-4-15 上午10:59:34
* @param args
*/
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<body>/**
* ID,长宽对象
* @author daniel
* @email [email protected]
* @time 2016-4-15 上午11:47:27
*/
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<body>/**
* 内存溢出d
* -server -Xms800m -Xmx800m -XX:PermSize=64M -XX:MaxNewSize=256m -XX:MaxPermSize=128m -Djava.awt.headless=true
* 发送文件到总部。导出sql 到excel。excel;
* excel用2003的老格式
* @author daniel
* @email [email protected]
* @time 2015-5-19 上午11:35:12
*/
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<body>/**
* 要生成的文件名
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* 日期注意格式
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<body>/**
* @author daniel
* @time 2015-5-19 上午11:35:03
* @param args
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<body>/**
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* @time 2015-5-19 上午11:48:47
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