Take url as input

[Lukkyz]

Hello,
I would like to know if it is possible now to take an URL as an input ?

[ralyodio]

I'm also wondering this. the example I have doesn't work

async start(url, user = null, pass = null) {
			console.log('Transcoding:', url);
			const headers = {};

			try {
				if (user && pass) {
					const encodedCredentials = Buffer.from(`${user}:${pass}`).toString('base64');
					headers['Authorization'] = `Basic ${encodedCredentials}`;
				}

				// Fetch the video from the URL
				const response = await fetch(url, { headers, redirect: 'follow' });

				if (!response.ok) {
					throw new Error(`Failed to fetch video: ${response.statusText}`);
				}

				// Create a readable stream from the response
				const videoStream = response.body;

				// Create a pass-through stream to handle ffmpeg output
				const stream = new PassThrough();

				// Pipe the video stream through ffmpeg to transcode it to mp4
				ffmpeg(videoStream)
					.format('mp4')
					.videoCodec('libx264')
					.audioCodec('aac')
					.on('error', (err) => {
						console.error('Error:', err.message);
						stream.destroy(err); // destroy the stream in case of error
					})
					.on('end', () => {
						console.log('Transcoding finished');
					})
					.pipe(stream, { end: true }); // ensure the stream ends properly

				return stream;
			} catch (err) {
				throw err;
			}
		}
		```

[ralyodio]

I guess ffmpeg doesn't support Response objects

[mrexox]

You can pass a URL as an input

ffmpeg().input('https://some-url.com/file.mp4')

If you want to pass some auth data it should be URL-encoded. Streaming must work for some protocols, but for mp4 it doesn't work since ffmpeg needs to do seek on the data. A bit more info: https://stackoverflow.com/questions/76479157/ffmpeg-via-pipe-stream-1-offset-0x30-partial-file

See also #1185