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slidingWindow.js
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//Whenver we've to find contigious subarry, use this method
//1. Max sum subarray of size k
//2. Smallest subarry from a given set
//3. Fruits in a basket
//4. Longest substring
//1. Max sum subarray of size k
function getMaxSum(arr, k) {
let sum = 0;
let start = 0;
let maxSum = 0;
for (let i = 0; i < arr.length - k + 1; i++) {
sum += arr[i];
if (i >= k) {
maxSum = Math.max(sum, maxSum);
sum -= arr[start];
start++;
}
}
return maxSum;
}
getMaxSum([2, 1, 5, 1, 3, 2], 7);
// 2. Find the smallest subarray from a given set
// Input: [2, 1, 5, 2, 3, 2], S=7
// Output: 2
// Explanation: The smallest subarray with a sum great than or equal to '7' is [5, 2].
function smallestSubarray(arr, k) {
let sum = 0;
let minLength = Infinity;
let start = 0;
for (let i = 0; i < arr.length; i++) {
sum += arr[i];
while (sum >= k) {
minLength = Math.min(minLength, i - start + 1);
sum -= arr[start];
start++;
}
}
if (minLength === Infinity) return 0;
return minLength;
}
console.log(smallestSubarray([3, 4, 1, 1, 6], 8));
//3. Fruits in a basket
// Given an array of characters where each character represents a fruit tree,
// you are given two baskets and your goal is to put maximum number of fruits in each basket.
// The only restriction is that each basket can have only one type of fruit.
// Input: Fruit=['A', 'B', 'C', 'A', 'C']
// Output: 3
// Explanation: We can put 2 'C' in one basket and one 'A' in the other from the subarray ['C', 'A', 'C']
function fruitsInBasket(arr) {
let maxFruits = 0;
let start = 0;
let fruitArr = {};
for (let i = 0; i < arr.length; i++) {
const curFruit = arr[i];
if (!(curFruit in fruitArr)) {
fruitArr[curFruit] = 0;
}
fruitArr[curFruit] += 1;
while (Object.keys(fruitArr).length > 2) {
console.log(fruitArr);
const leftFruit = arr[start];
fruitArr[leftFruit]--;
if (fruitArr[leftFruit] == 0) {
delete fruitArr[leftFruit];
}
console.log(fruitArr);
start++;
}
maxFruits = Math.max(maxFruits, i - start + 1);
}
return maxFruits;
}
console.log(fruitsInBasket(["A", "B", "C", "B", "B", "C"]));
//Longest substring
// Input: String="aabccbb"
// Output: 3
// Explanation: The longest substring without any repeating characters is "abc".
function longestSubstring(str) {
let maxLen = 0;
let start = 0;
let charIndexMap = {};
for (let i = 0; i < str.length; i++) {
let char = str[i];
if (char in charIndexMap) {
start = Math.max(start, charIndexMap[char] + 1);
}
charIndexMap[char] = i;
maxLen = Math.max(maxLen, i - start + 1);
}
return maxLen;
}
console.log(longestSubstring("aabaab!bb"));