1b9100be-2004-4947-84ba-f44a5b5fc6a3.html

<p class="os-raise-text-bold">Students will complete the following questions to practice the skills they have learned in this lesson.</p>
<p>For 1-4 use the problem below:</p>
<blockquote>Priya is buying raisins and almonds to make trail mix. Almonds cost $5.20 per pound, and raisins cost $2.75 per
  pound. Priya spent $11.70 buying almonds and raisins. The relationship between pounds of almonds, pounds of raisins,
  and the total cost is represented by the equation \(5.2a+2.75r=11.7\).</blockquote>
<p>How many pounds of raisins did Priya buy if she bought the following amounts of almonds?</p>
<ol class="os-raise-noindent">
  <li>2 pounds of almonds<br></li>
</ol>
<ul>
  <li>
    a.
    1.192
  </li>
  <li>
    b.
    2.75
  </li>
  <li>
    c.
    0.946
  </li>
  <li>
    d. 0.473
  </li>
</ul>
<p><strong>Answer:&nbsp;</strong> 0.473</p>
<p>\(5.2(2) + 2.75r = 11.7\)<br>
  \(10.4 + 2.75r = 11.7\)<br>
  \(10.4 + 2.75r - 10.4 = 11.7 - 10.4\)<br>
  \(2.75r = 1.3\)<br>
  \((1/2.75) (2.75r) = (1/2.75) (1.3)\)<br>
  \(r = 0.473\)</p>
<ol class="os-raise-noindent" start="2">
  <li>1.06 pounds of almonds<br></li>
</ol>
<ul>
  <li>
    2.25
  </li>
  <li>
    1.689
  </li>
  <li>
    5.5
  </li>
  <li>
    2.811
  </li>
</ul>
<p><strong>Answer:&nbsp;</strong> 2.25</p>
<p>\(5.2(1.06) + 2.75r = 11.7\)</p>
<ol class="os-raise-noindent" start="3">
  <li>0.64 pounds of almonds<br></li>
</ol>
<ul>
  <li>9.94
  </li>
  <li>1.911
  </li>
  <li>3.044
  </li>
  <li>8.371
  </li>
</ul>
<p><strong>Answer:&nbsp;</strong>3.044</p>
<p>\(5.2(0.64) + 2.75r = 11.7\)</p>
<ol class="os-raise-noindent" start="4">
  <li>\(a\) pounds of almonds<br></li>
</ol>
<ul>
  <li>\(r=\frac{11.7+5.2a}{2.75}\) </li>
  <li>\(r=\frac{11.7-2.75a}{5.2}\)
  </li>
  <li>\(r=\frac{2.75}{11.7-5.2a}\) </li>
  <li>\(r=\frac{11.7-5.2a}{2.75}\)</li>
</ul>
<p><strong>Answer:</strong>&nbsp;&nbsp;\(r=\frac{11.7-5.2a}{2.75}\)</p>
<p>\(5.2(a) + 2.75r = 11.7\)</p>
<br>
<p>For 5 and 6 use the problem below:</p>

<blockquote>A car traveled 180 miles at a constant rate.</blockquote>
<ol class="os-raise-noindent" start="5">
  <li> For each of the missing spaces in the table, a-d, select the missing value that
    completes the table to show the rate at which the car was traveling if it
    completed the same distance in each number of hours.</li>
</ol>
<table class="os-raise-skinnytable">
  <thead>
    <tr>
      <th scope="col">
        Travel Time<br>
        (Hours)
      </th>
      <th scope="col">
        Rate of Travel<br>
        (Miles Per Hour)
      </th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td>5</td>
      <td>a. ____ <br></td>
    </tr>
    <tr>
      <td>4.5</td>
      <td>b. ____ <br></td>
    </tr>
    <tr>
      <td>3</td>
      <td>c. ____ </td>
    </tr>
    <tr>
      <td>2.25</td>
      <td>d. ____ </td>
    </tr>
  </tbody>
</table>
<br>
<p><strong>CHOICES:&nbsp;</strong></p>
<ul>
  <li>40</li>
  <li>80</li>
  <li>36</li>
  <li>60</li>
</ul>
<p>a. ____ </p>
<p><strong>Answer:</strong>36</p>
<ol class="os-raise-noindent">
    <p>b. ____</p>
</ol>
<p><strong>Answer:</strong> 40</p>
<ol class="os-raise-noindent">
    <p>c. ____ </p>
</ol>
<p><strong>Answer:</strong> 60</p>
<ol class="os-raise-noindent">
    <p>d. ____</p>
</ol>
<p><strong>Answer:</strong> 80</p>
<ol class="os-raise-noindent" start="6">
  <li>Choose the equation that would make it easy to find the rate at which the car
    was traveling in miles per hour \(r\), if it traveled for \(t\) hours.</li>
</ol>
<ul>
  <li>\(r=\frac t{180}\)</li>
  <li>\(r=\frac{180}t\)</li>
  <li>\(r=180t\)</li>
  <li>\(r-180-t\)</li>
</ul>
<p><strong>Answer:</strong>&nbsp;&nbsp;\(r=\frac{180}t\)</p>
<ol class="os-raise-noindent" start="7">
  <li> Bananas cost $0.50 each, and apples cost $1.00 each. <br><strong>Select all three</strong>&nbsp;combinations of bananas
    and apples that Elena could buy for exactly $3.50.</li>
</ol>
<ul>
  <li>2 bananas and 2 apples</li>
  <li>3 bananas and 2 apples</li>
  <li>1 banana and 2 apples</li>
  <li>1 banana and 3 apples</li>
  <li>5 bananas and 2 apples</li>
  <li>5 bananas and 1 apple</li>
</ul>
<p><strong>Answer:</strong> “3 bananas and 2 apples” and “1 banana and 3 apples” and “5 bananas and 1 apple”</p>
<p>\(3(0.5)+2(1)=3.50\)<br>
  \(1(0.5)+3(1)=3.50\)<br>
  \(5(.5)+1(1)=3.50\)</p>
<ol class="os-raise-noindent" start="8">
  <li>Choose the best answer to solve the formula \(A=P+Prt\) for \(t\).</li>
</ol>
<ul>
  <li>\(t=\frac{P-A}{Pr}\)</li>
  <li>\(t=\frac{A-P}{Pr}\)</li>
  <li>\(t=\frac{A+P}{Pr}\)</li>
  <li>\(t=\frac{r(A-P)}P\)</li>
  <br>
</ul>
<p><strong>Answer:</strong>&nbsp;&nbsp;\(t=\frac{A-P}{Pr}\)</p>
<p>\(A=P+Prt\)<br>
  \(A-P=P-P+Prt\)<br>
  \(A-P=Prt\)<br>
  \(\frac{A-P}{Pr}=\frac{Prt}{Pr}\)<br>
  \(\frac{A-P}{Pr}=t\)</p>