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Question about the constrained quadratic problem #18

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jdumas opened this issue Sep 25, 2020 · 0 comments
Open

Question about the constrained quadratic problem #18

jdumas opened this issue Sep 25, 2020 · 0 comments

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@jdumas
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jdumas commented Sep 25, 2020

// The unknowns are x,y,z,u0,v0,u1,v1,1

Hi guys. Looking at the code of the quadratic problem, I was wondering why do you use the constant 1 as one of the unknown variable (through an equality). Is it there for numerical reasons, or something else?

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