Swift 6.1 regression creating AnyHashable from existential with parameter pack

[stephencelis]

Description

Code involving AnyHashable, existentials, and parameter packs that used to compile in Swift 6.0.3 no longer compiles in 6.1.

Reproduction

protocol Bar<T>: Hashable {
  associatedtype T
}
struct Foo<each T> {
  let x: any Bar<(repeat each T)>
  static func == (lhs: Foo, rhs: Foo) -> Bool {
    AnyHashable(lhs.x) == AnyHashable(rhs.x)     // 🛑
    /*
    // Workaround:

    let lhs = lhs.x
    let rhs = rhs.x
    return AnyHashable(lhs) == AnyHashable(rhs)  // ✅
     */
  }
}

Expected behavior

I expect this code to still compile in 6.1.

Environment

swift-driver version: 1.120.2 Apple Swift version 6.1 (swiftlang-6.1.0.106.4 clang-1700.0.9.2)
Target: arm64-apple-macosx15.0

Additional information

No response