There are n cities. Some of them are connected, while some are not. If city a is connected directly with city b, and city b is connected directly with city c, then city a is connected indirectly with city c.
A province is a group of directly or indirectly connected cities and no other cities outside of the group.
You are given an n x n matrix isConnected where isConnected[i][j] = 1 if the ith city and the jth city are directly connected, and isConnected[i][j] = 0 otherwise.
Return the total number of provinces.
Input: isConnected = [[1,1,0],[1,1,0],[0,0,1]]
Output: 2
class Solution {
public int findCircleNum(int[][] M) {
Uf uf = new Uf(M.length);
for(int i = 0; i < M.length; i++) {
for(int j = 0; j < M.length; j++) {
if(M[i][j] == 1) uf.union(i, j);
}
}
return uf.count;
}
class Uf {
int[] parent;
int count;
public Uf(int n) {
parent = new int[n];
for(int i = 0; i < n; i++) {
parent[i] = i;
}
count = n;
}
public int find(int i) {
while(parent[i] != i) {
parent[i] = parent[parent[i]];
i = parent[i];
}
return i;
}
public void union(int i, int j) {
int m = find(i);
int n = find(j);
if(m == n) return;
count--;
parent[n] = m;
}
}
}