use default timeout (#38)

Co-authored-by: Virasak Dungrikaew <[email protected]>

src/Agoda.DevFeedback.Common/DevFeedbackPublisher.cs

@@ -45,7 +45,6 @@ public static async Task PublishAsync(string apiEndpoint, object data, DevLocalD
             var targetEndpoint = GetApiEndpoint(devLocalDataType, apiEndpoint);
             using (var httpClient = new HttpClient())
             {
-                httpClient.Timeout = TimeSpan.FromSeconds(2);
                 var content = new StringContent(JsonConvert.SerializeObject(data), Encoding.UTF8, "application/json");
                 var response = await httpClient.PostAsync(targetEndpoint, content);
                 response.EnsureSuccessStatusCode();