interp: fix a missing implicit type conversion for binary expression

When parsing binary operator expressions, make sure that implicit type conversions for untyped expressions are performed. It involves walking the sub-expression subtree at post-processing of binary expressions.

Fixes #1653.

_test/issue-1653.go

@@ -0,0 +1,12 @@
+package main
+
+func f(b uint) uint {
+	return uint(1) + (0x1 >> b)
+}
+
+func main() {
+	println(f(1))
+}
+
+// Output:
+// 1

interp/cfg.go

@@ -984,6 +984,9 @@ func (interp *Interpreter) cfg(root *node, sc *scope, importPath, pkgName string
 				// Allocate a new location in frame, and store the result here.
 				n.findex = sc.add(n.typ)
 			}
+			if n.typ != nil && !n.typ.untyped {
+				fixUntyped(n, sc)
+			}
 
 		case indexExpr:
 			if isBlank(n.child[0]) {
@@ -2302,6 +2305,20 @@ func (interp *Interpreter) cfg(root *node, sc *scope, importPath, pkgName string
 	return initNodes, err
 }
 
+// fixUntyped propagates implicit type conversions for untyped binary expressions.
+func fixUntyped(nod *node, sc *scope) {
+	nod.Walk(func(n *node) bool {
+		if n == nod || (n.kind != binaryExpr && n.kind != parenExpr) || !n.typ.untyped {
+			return true
+		}
+		n.typ = nod.typ
+		if n.findex >= 0 {
+			sc.types[n.findex] = nod.typ.frameType()
+		}
+		return true
+	}, nil)
+}
+
 func compDefineX(sc *scope, n *node) error {
 	l := len(n.child) - 1
 	types := []*itype{}